Hello Experts,
Structure: 6 retention locations of antithetic sizes, each containing a container of the aforesaid size.
These locations are each disposable respective times.
The filling quantity of the boxes varies depending connected the worldly (upper bounds of filling quantity determined empirically).
Mixing with different materials is not desired.
An summation of the aforesaid materials up to the max. quantity is desired.
Example: goods receipt 300 pcs. of screws
In the Material maestro grounds astatine show LVS2 3 boxes/ LET are stored, LET1= 200 pcs, LET2=100 LET3=50 pcs
At the GR a TO is created with 2 positions, 1x200 connected LET1 & 1x 100 pcs connected LET2.
But... The effect successful the TO: The retention bin K1 with LET1 is filled with 300pcs. - 100 pcs. supra the maximum
So: Neither the capableness cheque nor the uncovering of the close 2nd retention bin fails (the LET occupies 1 unit, the retention bin has capableness 1, truthful lone 1 LET per bin)
Storage benignant Putaway strategy L, LET cheque activated, capableness cheque activated, cheque method 3 & 4,
Storage bin type, retention portion benignant defined and assigned
Putaway strategy P besides tried, but fails owed to the magnitude of the retention bin designation (max. 10 characters incl. /01 etc.)
No mistake messages, but the strategy ignores the limits and simply adds banal (which is what the strategy specifies) SU absorption is not activated for the retention type.
Does anyone cognize however to representation the desired scenario?
Greetings,
Roy